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-0078|“`
class Solution:
def removeElement(self, nums: List[int], val: int) -> int:
i = 0

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    # Iterate over the list
    while i < len(nums):
        # If the current element is equal to the value to remove
        if nums[i] == val:
            # Remove the element from the list
            nums.pop(i)
        # Otherwise
        else:
            # Increment the index
            i += 1

    # Return the length of the updated list
    return len(nums)

“The provided Python code defines aremoveElementfunction that takes a list of integers (nums) and an integer value (val) as input. This function modifies thenumslist in place by removing all occurrences of the specifiedval` and returns the number of elements remaining in the list after the removal.

Here’s a breakdown of the code:

1. Initialize an index variable i to 0. This variable will be used to iterate through the nums list.

2. Enter a while loop that continues as long as i is less than the length of the nums list (i.e., i < len(nums)). This loop iterates through each element in the nums list.

3. Inside the loop, check if the current element at index i is equal to the val value to remove. If they are equal, it means an instance of val has been found.

4. If nums[i] is equal to val, remove the current element from the nums list using the pop(i) method. pop(i) removes the element at index i and shifts the subsequent elements to fill the gap, effectively removing val from the list.

5. If nums[i] is not equal to val (i.e., it is a different value), it means the current element should be kept in the list. In this case, increment the index i by 1 to move to the next element.

6. After processing all elements in the list, return the length of the updated nums list using the len(nums) expression. This represents the number of elements remaining in the list after the removal of all val occurrences.

In summary, this code implements an efficient algorithm to remove all occurrences of a specific value (val) from a list (nums) while modifying the list in place. It iterates through the list and removes any elements matching the val value, returning the updated list’s length as the result.

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